Team total points odd/even strategy

The chances that the points scored by a team at a match to be strange or even are just like the odds of head and tail to come out once we flip the coin, meaning 50%. Notably in sports as basketball at which the scores are high and also the points occur more than one at a time. It’s just a game of numbers.
If we all know and we knoe that the true probability for each result is 50% we can use the legislation of binomial distribution to estimate the odds of events to occur in trials.
What I mean is that when a group has 6 consecutive odd total points, the chances that the 7th game the points scored to be odd are 0.062, 62 out of 1000. More if a team has 7 consecutive odd total points that the chances to become at the 8th are 0.035, 35 out of 1000. The probability will not become 0 or 9 consecutive chances but they are getting more closer to 0. Even at 35/1000, there are chances but just 35 at 1000 trilas.
The principal point is that Dallas Mavericks possess 6 successive odd total points so if we wager total points even for Dallas the chances to eliminate the wager are 6.2percent and Phoenix Suns have 7 consecutive odd totals so if we they will score tonight a total even the odds to lose are 3.5%.
I didn’t make any backtesting but it’s pure mathematics so I will take them good bets.

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